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(D) In the reaction $MnO_2 + 4HCl 	o MnCl_2 + 2H_2O + Cl_2$,the oxidation state of $Cl$ changes from $-1$ in $HCl$ to $0$ in $Cl_2$.The change in oxi

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$2M$

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(D) In the reaction $MnO_2 + 4HCl 	o MnCl_2 + 2H_2O + Cl_2$,the oxidation state of $Cl$ changes from $-1$ in $HCl$ to $0$ in $Cl_2$.The change in oxidation number for one $Cl$ atom is $1$. Since there are $2$ $Cl$ atoms in $Cl_2$,the total change in oxidation number for $4$ moles of $HCl$ is $2$.Therefore,the $n$-factor for $4 \ mol$ of $HCl$ is $2$.The $n$-factor for $1 \ mol$ of $HCl$ is $\frac{2}{4} = \frac{1}{2}$.Equivalent weight of $HCl = \frac{	ext{Molar mass}}{	ext{n-factor}} = \frac{M}{1/2} = 2M$.

What is the equivalent weight of hydrochloric acid in the given redox reaction $MnO_2 + 4HCl \to MnCl_2 + 2H_2O + Cl_2$?
If the molar mass of hydrochloric acid is $M$.

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What is the equivalent weight of hydrochloric acid in the given redox reaction $MnO_2 + 4HCl \to MnCl_2 + 2H_2O + Cl_2$?If the molar mass of hydrochloric acid is $M$.